X^2+x^2=22x^

Solution for X^2+x^2=22x^ equation:

X^2+X^2=22X^

We move all terms to the left:

X^2+X^2-(22X^)=0

We add all the numbers together, and all the variables

2X^2-22X=0

a = 2; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·2·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*2}=\frac{0}{4}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*2}=\frac{44}{4}
=11
$